Question

Find the sum of three digit numbers from 100-150​

Answer 1

sn= n/2 {2a+(n-1)d}

= 51 /2(200+50×1)

= 51/2 × 250

= 51× 125
= 6375

plz mark me brain list

hope it is helps you

Answer 2

Answer:

a= 100 d=1 Tn=150 to find n

Tn=a+(n-1)d

150=100+(n-1)1

50= n-1

n=51

to find sum using sum formula

S=n/2[2a+(n-1)d]

S=51/2[2x100+(51-1)1]

S=51/2[200+50]

S=51/2(250)

S=51x125

S=6375

therefore the sum is 6375

hope that helped..

plzz mark as brainliest