Question

find the sum of twice the first and thrice the second is 92 and four times the first exceeds seven time the second by 2, the numbers are

how to solve

Answer 1

hey, here is your ans.
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Answer 2

Hey dear here is your answer!!!!!!!

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$let \: the \: no. \: be \: x \: and \: y \: \\ \\now \: according \: to \: question \: \\ \\ 2x + 3y = 92 \\ 4x = 7y + 2 ......eq \: 1 \\ \\ subtitute \: value \: of \: x \: from \: 1 \\ \\ 2(7y + 2)/4 + 3y = 92 \\ 14y \: 7y + 2+6y = 184 \\ 13y = 182 \\ y = 14 \div 17$
On substitution of y in eq. 1

We will get x= 25

Hope it helps u dear...✳️✴️✴️