Find the sum of two consecutive no? If the difference of squares of the two numbers is 19.
(a) 19
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Answer:
let 1st no=x
2nd consecutive no=x+1
ATQ
(x+1)^2-x^2=19
x^2_2x+1-x^2=19
2x+1=19
x=18/2
=9
1st no=9
2nd no=9+1=10Ans
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