find the sum of two digit number which are divisible by7
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Lets form the AP
AP:- 14,21,28..........98
Therefore,
a=14
d=7
an=98
an= a + (n-1) × d
98= 14 + (n-1) ×7
98-14= 7n - 7
84= 7n - 7
84+7= 7n
91= 7n
91/7= n
n=13
Sn = n/2 (a+an)
Sn = 13/2 (14+98)
Sn = 13/2 (112)
Sn = 6.5 (112)
Sn = 728
=>The sum 2 digit numbers which are divisible by 7 are 728
AP:- 14,21,28..........98
Therefore,
a=14
d=7
an=98
an= a + (n-1) × d
98= 14 + (n-1) ×7
98-14= 7n - 7
84= 7n - 7
84+7= 7n
91= 7n
91/7= n
n=13
Sn = n/2 (a+an)
Sn = 13/2 (14+98)
Sn = 13/2 (112)
Sn = 6.5 (112)
Sn = 728
=>The sum 2 digit numbers which are divisible by 7 are 728
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