find the sum of two middle terms of the AP.: -4/3,-1,-2/3,-1/3,...,13/3
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Answered by
4
-15,-11.....53
d = -11-(-15) = -11+15 = 4 d=4
L/aⁿ = a+(n-1)d
53= -15 + (n-1)4
53+15 = 4n-4
68+4 = 4n
72/4 = n
18 = n
we have to find the value of the middl n/2 = 18/2 = 9th term will be the middle term
9th term = a+(9-1)d = -15+ (8)4 = -15+32 = 17
So, the answer is 17.
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1
Answer:
17 is the best answer Mark
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