Find the sum of upto "n" term
( 0.6+0.66+0.666)
Cutiepieannu:
hiii
you have written nice bio
Answers
Answered by
1
Answer:
Let S
n
=0.6+0.66+0.666+... to n terms.
Then,
S
n
=0.6+0.66+0.666+... to n terms
⇒S
n
=
9
6
(0.1+0.11+0.111+... to n terms )
⇒S
n
=
9
6
{0.9+0.99+0.999+...tonterms}
⇒S
n
=
9
6
{(1−
10
1
)+(1−
10
2
1
)+(1−
10
3
1
)+...+(1−
10
n
1
)}
⇒S
n
=
9
6
{n−(
10
1
+
10
2
1
+
10
3
1
+...+
10
n
1
)}
⇒S
n
=
9
6
⎩
⎪
⎪
⎪
⎨
⎪
⎪
⎪
⎧
n−
10
1
1−
10
1
(1−(
10
1
)
n
)
⎭
⎪
⎪
⎪
⎬
⎪
⎪
⎪
⎫
=
9
6
{n−
9
1
(1−
10
n
1
)}
Answered by
1
ভোগালী বিহুৰ ওলগ জনালোঁ।
Similar questions