Question

find the sum of whose ap is .9 .91 .92 upto the 100​

Answer 1

Answer:

139.5

Step-by-step explanation:

Here,

First term, a=0.90

Common difference, d=0.01

Sum of first 100 terms= S₁₀₀=(100/2)x(2x0.90+99x0.01)

                                             =50x(1.80+0.99)

                                             =50x2.79

                                             =139.5

PLEASE RATE, THANK AND MARK AS BRAINLIEST.

Answer 2

Step-by-step explanation:

Let a1 = .9

a2=.91

a3= .92 ,... 100 terms

first term = a= a1 = 0.9

common difference = d= a2-a1 = .91- 0.9 = 0.01

number of term = n= 100

sum of n terms in Ap = Sn = n/2[2a+(n-1)d]

= 100/2 [2*0.9 + (100-1) (0.01)]

= 100/2 [ 1.8 +99*0.01]

= 100/2 (1.8 +0.99)

= (100 *2.79)

=279

s100 = 279