Question

Find the sum of x- and y- intercepts of the line 4x-5y=20. no spam

Answer 1

$\textbf{Given:}$

$\text{Equation of line is}\;4x-5y=20$

$\textbf{To find:}$

$\text{The sum of x and y intercepts}$

$\textbf{Solution:}$

$\text{Consider,}$

$4x-5y=20$

$\text{Divide bothsides by 20, we get}$

$\dfrac{4x}{20}-\dfrac{5y}{20}=\dfrac{20}{20}$

$\dfrac{x}{5}-\dfrac{y}{4}=1$

$\dfrac{x}{5}+\dfrac{y}{(-4)}=1$

$\text{Comparing this equation with}$

$\boxed{\bf\dfrac{x}{a}+\dfrac{y}{b}=1}$

$\text{we get}$

$\text{x-intercept,}\;a=5$

$\text{y-intercept,}\;b=-4$

$\text{Sum of the intercepts}$

$=a+b$

$=5+(-4)$

$=1$

$\textbf{Answer:}$

$\textbf{Sum of the x and y intercepts is 1}$

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Answer 2

Answer:

1 is the answer of this question