Math, asked by jydesai96, 9 months ago

find the sum of x square + 3 y square + 6 x square 2 x square minus y square + 8 x y + 8 and subtract the minus 3 X square + 4 y square + 3 + 4 x y square + - 5 ​

Answers

Answered by fab13
3

Answer:

 {x}^{2}  + 3{y}^{2}  + 6 {x}^{2} +  2 {x}^{2} -  {y}^{2}  + 8xy + 8 - 3 {x}^{2}  + 4 {y}^{2}  + 3 + 4xy^{2}  - 5 \\  = ( {x}^{2}   + 6 {x}^{2}  + 2 {x}^{2}   - 3 {x}^{2} )+ (3 {y}^{2}  -  {y}^{2}  + 4 {y}^{2})  + 4xy^{2}  + 8xy + (8 + 3 - 5) \\  = 6 {x}^{2}  + 6 {y}^{2}  + 4xy ^{2}  + 8xy + 6

Answered by ambica36
7

Step-by-step explanation:

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