Question

find the sum of x square + 3 y square + 6 x square 2 x square minus y square + 8 x y + 8 and subtract the minus 3 X square + 4 y square + 3 + 4 x y square + - 5 ​

Answer 1

Answer:

${x}^{2} + 3{y}^{2} + 6 {x}^{2} + 2 {x}^{2} - {y}^{2} + 8xy + 8 - 3 {x}^{2} + 4 {y}^{2} + 3 + 4xy^{2} - 5 \\ = ( {x}^{2} + 6 {x}^{2} + 2 {x}^{2} - 3 {x}^{2} )+ (3 {y}^{2} - {y}^{2} + 4 {y}^{2}) + 4xy^{2} + 8xy + (8 + 3 - 5) \\ = 6 {x}^{2} + 6 {y}^{2} + 4xy ^{2} + 8xy + 6$

Answer 2

Step-by-step explanation:

Hope it is helpful for you.