Question

find the sum of x+y+z in the following figure 50, degree 60 degree 70 degree​

Answer 1

Answer:

the sum of the measures of interior angles of a quadrilateral is 360∘

Also,115∘+70∘+60∘=245∘

∴∠ABC=360∘−245∘=115∘

Now, x=ext∠BCD

=180∘−115∘=65∘

y=180∘−70∘=110∘

z=180∘−60∘=120∘

w=180∘−115∘=65∘

∴x+y+z+w=65∘+110∘+120∘+65∘=360∘

Answer 2

Answer:

Since, the sum of the measures of interior angles of a quadrilateral is 360∘

Also,115∘+70∘+60∘=245∘

∴∠ABC=360∘−245∘=115∘

Now, x=ext∠BCD

=180∘−115∘=65∘

y=180∘−70∘=110∘

z=180∘−60∘=120∘

w=180∘−115∘=65∘

∴x+y+z+w=65∘+110∘+120∘+65∘=360∘