Question

find the sum of zero of 4u2+8u​

Answer 1

Answer:

4u² + 8u

Factorize the equation

Compare the equation with au² + bu + c = 0

We get

a = 4 ,b=-8 c= 0

To factorize the value we can take 4u common there

4u(u+2) = 0

First zero

4u = 0

U = 0

second zero

u+2 = 0

u = - 2

sum of zero 0 - 2 = - 2

product of zero 0 x ( - 2 ) = 0

Sum of zero -b/a = -(8/4) = -2

Product of zero c/a = 0/4 = 0

Hope it will help u