Find the sum of zero of p(x)=2xsquare-9x+10
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9/2
Given:- p(x) = 2x² - 9x + 10
, we know that sum of zeros = -b/a
here, a = 2
b = -9
and c = 10
now, alpha + beeta = - (-9) / 2
= 9/2
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