Question

find the sum of zeroes of quadratic polynomial t² -15​

Answer 1

Answer:

$0$

Step-by-step explanation:

$t^{2}-15=0$

$= (t+\sqrt{15})(t-\sqrt{15})=0$  $($∵ $a^{2}-b^{2}=(a+b)(a-b))$

$t+\sqrt{15}=0$

$t=-\sqrt{15}$

$t-\sqrt{15}=0$

$t=\sqrt{15}$

∴ The zeroes of the given quadratic polynomial are $\sqrt{15}$ and $-\sqrt{15}$

$\sqrt{15}+(-\sqrt{15} )$

$=\sqrt{15}-\sqrt{15}$

⇒ $0$

The sum of zeroes of the given quadratic polynomial is $0$.

Answer 2

ANSWER:

t²-15=0

t=+ or - root15

so

t=+15

or t= -15