Find the sum of zeroes of the polynomial 6x² – 2x + 5
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If f(x) = ax2+bx+c
Sum = -b/a = -(-2)/6 = 1/3
Sum = -b/a = -(-2)/6 = 1/3
Answered by
1
Answer:
Step-by-step explanation:
The polynomial 6x² – 2x + 5 does not have zeros in the set of real numbers.
D = b² - 4ac = ( - 2)² - 4(6)(5) = - 116 < 0
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