Find the sum of zeroes of the polynomial x^2 -3x -m(m+3)
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The sum of zeroes is 0 and the product of zeroes is -3.
Step-by-step explanation:
Recall the identity a
2
−b
2
=(a−b)(a+b).
Using it, we can write : x
2
−3=(x−
3
)(x+
3
).
So, the value of x
2
−3 is zero when x=
3
or x=−
3
.
Therefore, the zeroes of x
2
−3 are
3
and −
3
Now, sum of zeroes =
3
−
3
=0
product of zeroes =(
3
)(−
3
)=−3
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