Question

Find the sum of zeroes of the quadratic polynomial x²-9​

Answer 1

Answer:

x²-9

(x+3) (x-3)

x = 3, -3

α=3   β=-3

α+β = -b/a = 0/1

= 0

also, 3+ (-3) = 3-3 = 0

Answer 2

The sum of the zeros of the quadratic polynomial $x^2-9$ is zero(0).

Step-by-step explanation:

The given quadratic polynomial is  $x^2-9$

$=x^2+0x-9$

Here, a = 1, b = 0 and c = - 9

To find, the sum of the zeros of the quadratic polynomial $x^2-9$ = ?

Let α and β be the zeros of the given quadratic polynomial.

The sum of the zeros of the quadratic polynomial,

α + β = $\dfrac{-b}{a}$

∴ The sum of the zeros of the quadratic polynomial $x^2-9$

$=\dfrac{-0}{1}$

= 0

Thus, the sum of the zeros of the quadratic polynomial $x^2-9$  is zero(0).