Question

Find
the sum of zeros of polynomial
P(x) = 2x² - 9x+10.​

Answer 1

Answer:

2x²-9x+10

a=2 b= -9 c= 10

sum of zeros= -b/a

-(-9)/2 = +9/2

Answer 2

The sum of zeros of the given polynomial( α + β) = $\dfrac{9}{2}$ or, 4.5

Step-by-step explanation:

The given polynomial:

P(x) = 2$x^2$ - 9x + 10

Here, a = 2, b = - 9 and c = 10

Let α and β are the zeros of the polynomial.

To find, the sum of zeros of the given polynomial( α + β) = ?

We know that,

The sum of the zeros of the polynomial,

α + β = $\dfrac{-b}{a}$

= $\dfrac{-(-9)}{2}$

= $\dfrac{9}{2}$ or, 4.5

∴ The sum of zeros of the given polynomial( α + β) = $\dfrac{9}{2}$ or, 4.5