Question

find the sum of zeros of the polynomial x^2 -x-20​

Answer 1

Answer:

1

Step-by-step explanation:

we know that sum of the zeros of a quadrtic eqn is = (-b/a)

here b = (-1) and c = 1

PLEASE FIND THIS ATTACHMENT.

HOPE THIS WILL HELP U.

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Answer 2

$\bf{\underline{\underline{Given\: :}}}$

$\mathsf{Polynomial = x^{2} - x - 20}$

$\bf{\underline{\underline{To\:find}}}$

$\mathsf{Sum\:of\:the\:zeroes}$

$\bf{\underline{\underline{Solution\: :}}}$

$\mathtt{\implies\: x^{2} - x - 20 = 0}$

$\mathtt{\implies\: x^{2} + 4x - 5x - 20 = 0}$

$\mathtt{\implies\: x(x + 4) - 5(x + 4) = 0}$

$\mathtt{\implies\: (x - 5) (x + 4) = 0}$

$\mathtt{\implies\: x = 5 \: ; \: x = -4}$

$\mathtt{Sum\:of\:zeroes}$

$\mathtt{\rightarrow\: 5 + (- 4)}$

$\mathtt{\rightarrow\: 5 - 4}$

$\Large{\fbox{\mathtt{\green{\rightarrow\: 1}}}}$