find the sum of zeros quadratic polynomial x2+13x +42
Answers
Answered by
5
Step-by-step explanation:
p (x) = x2 +13x + 42
a = 1 , b = 13 , c = 42
sum of zeroes = -b/a
=> -(13)/1 = -13
Answered by
2
Answer:
x2+13x+42=0
sum of zeroes or roots is equals to = -b/a
here b=13, a=1
sum of zeroes = -13/1= -13
Similar questions