find the sum ofthe first 25 multiples of 8
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Answered by
8
Answer:
Step-by-step explanation:
→ The formula of sum of arithmetic series given the first term and common difference and the number of term.
= n/2 [ 2(a₁) + (n-1) (d)]
→ a₁ = 8 n = 25 d = 8
= 25/2 [ 2(8) + (25-1)(8)]
→ S₂₅ = 25/2 [16 + (24)(8) ]
→ S₂₅ = 25/2 [16 + 192]
→ S₂₅ = 25/2 (208)
→ S₂₅ = 25 (104)
→ S₂₅ = 2,600
Answered by
5
Sum of first 25 multiples of 8
....
8+16+24+32+40+48+56+64+72+80+88+96+104+112+120+128+136+144+152+160+168+176+184+192+200
Take 8 as common
8(1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+19+20+21+22+23+24+25)
....
=8(325)
....
=2600
Hope this may help you
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