Question

find the sum on which the compound interest for 2 years at 10% p.a is ₹154

Answer 1

Let the required sum be x

then, $x(1+\frac{10}{100})^{2} -x=154\\\\x(\frac{11}{10})^{2} -x =154\\\\\frac{121x}{100}-\frac{x}{1} =154$

$\frac{21x}{100}=154\\ x=154(\frac{100}{21}) \\x=\frac{2200}{3} =733.3$

Answer 2

Let the required sum be x

then, \begin{gathered}x(1+\frac{10}{100})^{2} -x=154\\\\x(\frac{11}{10})^{2} -x =154\\\\\frac{121x}{100}-\frac{x}{1} =154\\\end{gathered}

x(1+

100

10

)

2

−x=154

x(

10

11

)

2

−x=154

100

121x

−

1

x

=154

\begin{gathered}\frac{21x}{100}=154\\ x=154(\frac{100}{21}) \\x=\frac{2200}{3} =733.3\end{gathered}

100

21x

=154

x=154(

21

100

)

x=

3

2200

=733.3