Question

find the sum on which the compound interest is 10% per annum for three years is ₹331​

Answer 1

Answer:

=> P = ₹1,000

Step-by-step explanation:

Let see your answer !!!!!

Given that

C.I. = ₹331

R = 10 % p.a.

T = 3 years

P = ?

Solution

C.I. = P[(1 + R/100)^n - 1]

=> 331 = P[(1 + 10/100)^3 - 1]

=> 331 = P[(100 + 10/100)^3 - 1]

=> 331 = P[(110/100)^3 - 1]

=> 331 = P[(11/10)^3 - 1]

=> 331 = P[1,331/1,000 - 1]

=> 331 = P[1,331 - 1,000/1,000]

=> 331 = 331P/1,000)

=> P = 331 × 1,000/331

=> P = ₹1,000

Answer 2

Answer:

given , r=10%

CI = ₹331

time= 3 years

Step-by-step explanation:

CI = p [ (1+ r/100)^t -1]

331 = P [ (1+ 10/100)³ -1]

331 = P [ (1+ 1/10)³- 1]

331 = P [ (11/10)³ -1]

331 = P [ 1331-1000/1000]

331 = P × 331/1000

P = (1000 × 331) ÷ 331

P = ₹1000