Find the sum on which the difference between the simple interest and the compound intrest at the rate of 8%per annum compounded annuly be ₹64 in 2 years
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Heya friend,
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Let ₹P be the principal. Then,
S.I. = P × R × T/100
= P × 8 × 2/100
= ₹ 4P/25
C.I. = P{(1+R/100)^n - 1
= P{(1+8/100)^2 - 1
= P{(100+8/100)^n - 1
= P{(108/100)^2 - 1
= P{(27/25)^2 - 1
= P{729/625 - 1}
= P{729-625/625}
= P{104/625}
= ₹104P/625
According to question,
C.I. - S.I. = 64
=> 104P/625 - 4P/25 = 64
=> 104P - 100P/625 = 64
=> 4P/625 = 64
=> P = 64 × 625/4
=> P = ₹10,000
Hence, the sum is ₹10,000.
Thanks
With regards@
Tanisha
◆◆◆◆◆◆◆◆◆◆◆◆◆◆◆◆◆◆◆◆◆◆◆
Let ₹P be the principal. Then,
S.I. = P × R × T/100
= P × 8 × 2/100
= ₹ 4P/25
C.I. = P{(1+R/100)^n - 1
= P{(1+8/100)^2 - 1
= P{(100+8/100)^n - 1
= P{(108/100)^2 - 1
= P{(27/25)^2 - 1
= P{729/625 - 1}
= P{729-625/625}
= P{104/625}
= ₹104P/625
According to question,
C.I. - S.I. = 64
=> 104P/625 - 4P/25 = 64
=> 104P - 100P/625 = 64
=> 4P/625 = 64
=> P = 64 × 625/4
=> P = ₹10,000
Hence, the sum is ₹10,000.
Thanks
With regards@
Tanisha
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