find the sum or the zeroes of the quadratic polynomial x square - 9
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Answered by
8
Answer:
Given,
P(x)=x²-9
Sum of zeroes=-b/a=-0/1=0.
Answered by
7
The sum or the zeroes of the quadratic polynomial x square -9 is 0.
Stepwise explanation is given below:
- f(x) = ax² + bx + c ..... (1)
α and β be the zeros of f(x), then
α + β = - b/a
αβ = c/a
- The given polynomial is (x² - 9)
Now, x² - 9
= x² + 0 * x + (- 9)
- Comparing it with equation (1), we can write
α + β = - b/a
p + q = - 0/1 = 0
- We need to find out only the sum
where p, q are the zeros of (x² - 9)
- Therefore, the sum of the zeros of the given quadratic polynomial is 0.
But there can be one more zero
αβ = c/a
- Comparing it with equation (1), we can write
pq = (- 9)/1 = - 9.
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