Question

Find the sum the first 30 positive INTEGERS DIVISIBLE by 6​

Answer 1

Step-by-step explanation:

a=6

d=6

an=30

an =a+(n-1)d

30=6+(n-1)6

n-1*6=24

n-1=4

n=5

s5=5/2(12+24)

5/2*36

5*18=90

Answer 2

Answer:

$\texttt{Question}$

Find the sum the first 30 positive INTEGERS DIVISIBLE by 6

Step-by-step explanation:

At 1st 30 numbers are there and we have to find their sum-

a=6

d=6

an=30

an=a+(n-1)d

30=6+(n-1)×6

30-6=(n-1)×6

24/6=n-1

4=n-1

4+1=n

5=n

OR

30/6=5 TOTAL 5 TERMS✓

S5=5/2[2a+(5-1)×d]

S5=5/2[2×6+4×6]

5/2[12+24]=S5

5/2×36=5×18=S5

90=S5

HOPE YOU UNDERSTOOD ™✓