Find the sum to 20 terms of the series 6 + 30 + 70 +126 + ... ... ... ...
Answers
Answered by
0
Answer:
Sn= n/2[2a+(n-1)d]
S20=20/2 [2×6+(20-1)24]
=10 [12+(19)24]
=10 [12+456]
=10×468
=4680
Similar questions