Question

Find the sum to 200 terms of the series 2 + 5 + 7 + 6 + 12 + 7 + ....

Answer 1

Sum (200) = 200/2 × [4 + (199)3]

= 100 × [4 + 597]

= 100 × 601

= 60100

Answer 2

Hey mate ^_^

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Answer:
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$Sum$ = $( \frac{n}{2} )[2a + (n - 1)d]$

$= \frac{200}{2} \times [4 + (199)3]$

$= 100 \times [4 + 597]$

$= 100 \times 601$

$= 60100$

Therefore,

Answer is 60100

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