Find the sum to n terms
0.5+0.55+0.555+.........upto n terms.
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Answer:
Step-by-step explanation:
Sum of n terms = n(2a+(n-1)d)/2
therefore,
n(0.5*2+(n-1)0.5)/2
n(0.25+0.5n-0.5)/2
n(0.5n-0.25)/2
0.5n(n-0.5)/2
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