find the sum to n terms
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a= 1 , A2( second term) = 5. , d= 5- 1=4
Sn= n/2 ( 2a +(n-1)d )
Sn =n/2 (2× 1 + (n-1)x 4
Sn= n/2 (2+4n-4)
Sn =n/2 (4n-2)
Sn=4n^2 -2n/2
Sn= 2(2n^2 -n)/2
Sn= 2n^2 -n
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