Math, asked by poonam27kumawat, 11 months ago

find the sum to n terms
(2n – 1)²

Answers

Answered by Anonymous

1

answer :

$({2n - 1})^{2} \\ ({2n})^{2} + {(1)}^{2} - 2(2n)(1) \\ {4n}^{2} + 1 - 4n$

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