Question

find the sum to n terms of the AP whose k^th term is 5K + 1​

Answer 1

Here,

First term = a = 5(1) + 1 = 6

Second Term = a2 = 5(2) + 1 = 11

d = 11 - 6 = 5

$sum \: = \: \frac{k}{2} \times (6 + 5k + 1) = \frac{k(5k + 7)}{2} \\ = \frac{5 {k}^{2} + 7k}{2}$

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Answer 2

Answer:

First term = a = 5(1) + 1 = 6

Second Term = a2 = 5(2) + 1 = 1

d = 11 - 6 = 5\begin{gathered}sum \: = \: \frac{k}{2} \times (6 + 5k + 1) = \frac{k(5k + 7)}{2} \\ = \frac{5 {k}^{2} + 7k}{2} \end{gathered}

sum=

2k ×(6+5k+1)= 2k(5k+7)= 25k 2 +7k

Step-by-step explanation:

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