find the sum to n terms of the AP whose kth term is 5K + 1
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as kth term is 5k+1
first term would be 5(1)+1
a=6
similarly 2nd term would be
5(2)+1
11
on subtracting A1 from A2
we will get d = 5 which is the common difference.
as sn = n/2(2a+(n-1)d)
=n/2(12+(n-1)5)
=n/2 (12-5+5n)
n/2(7+5n)
would be the sum
hope it is correct
first term would be 5(1)+1
a=6
similarly 2nd term would be
5(2)+1
11
on subtracting A1 from A2
we will get d = 5 which is the common difference.
as sn = n/2(2a+(n-1)d)
=n/2(12+(n-1)5)
=n/2 (12-5+5n)
n/2(7+5n)
would be the sum
hope it is correct
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