Find the sum to n terms of the sequence 1,3,5....
(A) [n-1]^2
(B) [n+1]^2
(C) [2n-1]^2
(D) n^2
Answers
Answered by
3
Hi Mate!!!
Sn = n / 2 [ 2a + (n-1) d]
a = 1. d = 3-1 = 2
Sn = n /2 [ 2 + 2n - 2 ]
Sn = 2n² / 2
Sn = n²
Have a nice time
Sn = n / 2 [ 2a + (n-1) d]
a = 1. d = 3-1 = 2
Sn = n /2 [ 2 + 2n - 2 ]
Sn = 2n² / 2
Sn = n²
Have a nice time
Answered by
2
Answer:
so the answer is n2
Step-by-step explanation:
sn=n/2[2a+(n-1)d] if we use the formula or use sn=n/2(a+1)
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