Question

find the sum to n terms of the series , whose nth term is given by (2n - 1)*2​

Answer 1

Answer:

nth term=(2n-1) ×2

ist term =(2×1-1) ×2=2

second term=(4-1) ×2=6

3rd term=(6-1) ×2=10

so, series is given

2,6,10,.....(2n-1) ×2

this series is inA. P

d=10-6=6-2=4

istam term a=2

sum of nth term is =n/2[2a+(n-1) d]

Sn=n/2[2×2+(n-1) ×4]=n/2[4+4n-4]=n/2 *4n=2n²

Sn=2n².

Mark as Brainlist answer.