Question

Find the sum upto n terms
1/(1*2)+1/(2*3)+1/(3*4)+....

Answer 1

Solution :

1/(1•2)+1/(2•3)+

1/(3•4)+..nterms

= [1/1-1/2]+[1/2-1/3]+[1/3-1/4]

+ ...+ [1/(n-1)-1/n]

After cancellation, we get

= 1 - 1/n

= ( n - 1 )/n

••••

Answer 2

hope it helps you.....