Question

find the sum using algebraic identity (2x-y-z)^2​

Answer 1

Answer:

4$x^{2}$ + $y^{2}$ +$z^{2}$ - 4xy - 2yz - 4zx

Step-by-step explanation:

we know the formula $(a-b-c)^{2}$ = $a^{2} + b^{2} + c^{2} - 2xy - 2 yz - 2zx$

so ($(x^{2} + y^{2} +z^{2} )^{2} =$ 4$x^{2}$ + $y^{2}$ +$z^{2}$ - 4xy - 2yz - 4zx