Question

Find the sum which becomes of 65210amount in 3years at 8%per annum simple interest

Answer 1

Answer:

₹27,125

Step-by-step explanation:

S.I = 6510/-

T = 3 years

R = 8%

To Prove: The principal.

Proof: Let the principal be P.

We Know that—

S. I. = (P×R×T) /100

₹6510=(P×8%×3)

P= ₹(8/100×3×6510)

P= ₹27125

Hence, The principal will be 27,125.

Answer 2

Let P be the principal sum.

As we know that,

S.I.=

$\frac{p \times r \times t}{100}$

Whereas,

S.I.= Simple interest

P= Principal sum

r= Rate

t= times

Therefore,

Condition I:- For 3 years at the rate of 8% per annum.

S.I.=

$\frac{p \times 8 \times 3}{100}$

⇒24P=18P=9600

⇒24P−18P=9600

P=>

$\frac{9600}{6}$

=1600

Hence the sum is Rs.1600.

Hence the correct answer is 1600