Question

Find the sum which will amount to ₹ 6600 in 4 years at 8% rate per year.

Answer 1

• As per the data given in the question, we have to find the value of the expression.

           Given data:- $Rs.\ 6600$ in $4$ years at $8\%.$ rate per year.

           To find:- Sum which will amount to $Rs.6600$ in $4$  a year.

           Solution:-

                  $\text { Principal=Rs } 100\\\text { Interest=Rs8 }\\\text { Therefore interest for } 4 \text { years }=8^{*} 4=\mathrm{Rs} 32\\\text { Amount=Rs } 32+100=\text { Rs } 132\\\text { Amount=Rs } 6600 \text { (given) }\\\text { Therefore principal of Re } 1=6600 / 132=\text { Rs } 50\\\text { Therefore principal for Rs } 100=50^{*} 100=\text { Rs } 5000.$

              Hence we will get Rs.$5000.$

Answer 2

Given: Amount= Rs.$6600$, Time= $4$yrs, and rate=$8$%.

We have to find the sum.

We are solving in the following way:

$\text { Let the sum which will amount to Rs } 6,600 \text { in } 4 \text { years @ } 8 \% \text { per annum be } P \text {. }$

As we know that the formula to calculate the simple interest is $I=\frac{P \times r \times t}{100}$

Hence we have,

$=>I=\frac{P \times 8 \times 4}{100}\\\\=>I=\frac{8 P}{25}$

We know that the amount A is given by$A=I+P$

Hence we have,

$=>A=\frac{8 P}{25}+P\\\\=>A=\frac{33 P}{25}$

$\text { But given that } A=6600$

Hence we have,

$\frac{33 P}{25}=6600$

$\text { Multiplying both sides by } 25 \text {, we get }$

$33 P=25 \times 6600$

$\text { Dividing both sides by } 33 \text {, we get }$

$P=\frac{25 \times 6600}{33}\\\\P=25 \times 200\\\\P=5000$

Hence, the sum which will amount to Rs $6600$ @ $8$% per annum for$4$ years at simple interest is Rs. $5000$