Question

Find the sum without adding 1) 1+3+5+7 2) 1+3+5+7+9+11 (ch squares and square roots class 8th ( with explanation how comes answer)​

Answer 1

Step-by-step explanation:

here , we used a formula

sum of first " n"odd number = n^2

1.) 1+3+5+7=(4)^2 =16

2.) 1+3+5+7+9+11= (6)^2=36

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Answer 2

Answer:

The answer is 16 .

Step-by-step explanation:

On looking at the series of numbers 1+3+5+7 , we notice that all the numbers are odd.

1.) So we will count how many numbers are there , on counting , there are 4 numbers.

2.) As there are only 4 numbers , we will get the answer when we will find the square of the number 4 .

3.)(4)^2 = 4×4

=16

4.) If you want to verify the answer , then simply add the numbers you will get the same answer .

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Now , in second question , on counting there are 6 numbers , so we will find the square of 6

6^2=6×6 =36

The answer is 36 . You can verify the answer by adding the numbers again .

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