find the summ off integers between 100 and 500 which are divisible by 9
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The integers between 100 & 500 divisible by 9 are 108, 117, 126.........,495.
a = 108. d = 9. l = 495
According to the question :
⟹an=a+(n−1)d
⟹495=108+(n−1)9
⟹495=108+9n−9
⟹495=9n+99
⟹9n=495−99
⟹9n=396
⟹n= 396/9
=> n = 44
Sn = n/2(a+l)
=> Sn = 44/2 * (105+495)
=> Sn = 22*600
=> Sn = 13200
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