Question

Find the summation of all the digits of the numbers from 1 to 444. If the digit is more than once in a number, you have to count them separately.

Answer 1

W.K.T > (n+n²) |

2 |

SO ,, 444+444²

2

444+197136 = 1,97,580

2 2

> SO THE ANSWER IS = 98790...

Answer 2

Answer:

The summation of all the digits of the numbers from 1 to 444 is

98790...

Step-by-step explanation:

As per the question,

Given That :

the digits of the numbers from 1 to 444.

So n=444

digit is more than once in a number, you have to count them separately.

To Find:

the summation of all the digits of the numbers from 1 to 444.If the digit is more than once in a number, you have to count them separately.

Solution:

We know that,

$\frac{n+n^{2} }{2}$

$\frac{444+444^{2} }{2}$

$\frac{444+197136}{2}$

$=\frac{197580}{2}$

$=98790....$

Therefore,  the summation of all the digits of the numbers from 1 to 444 is

98790... If the digit is more than once in a number, you have to count them separately.

For more such type of questions:

https://brainly.in/question/41891824

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