Question

find the summation of the odd numbers from 1 to 201​

Answer 1

Answer:

1+2+3+4+5…..+201

S201 = 201 (1+201)/2=101×201

Sum of even

2+4+6+8+……200

=2 [1+2+3+4+…..+100]

S( even)= 2 [ 100 (100+1)/2 =100×101

S(odd)= S201 - S(even)

……… =(101×201)-(100×101)

……….=101 (201-100)

……… = 101×101=10201

Or

We have to find out

1+3+5+7+……..+201

Number of terms =101

First term = 1

Last term = 201

In any AP series sum of series is =

Sn =n [a+l]/2 Where n= number of terms

a =first term and .. l= last term

Sum of odd = 101 (1+201)/2= 101×101 =10201

Step-by-step explanation:

Answer 2

Answer:

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Explanation:

1+2+3+4+5…..+201

S201 = 201 (1+201)/2=101×201

Sum of even

2+4+6+8+……200

=2 [1+2+3+4+…..+100]

S( even)= 2 [ 100 (100+1)/2 =100×101

S(odd)= S201 - S(even)

……… =(101×201)-(100×101)

……….=101 (201-100)

……… = 101×101=10201

Or

We have to find out

1+3+5+7+……..+201

Number of terms =101

First term = 1

Last term = 201

In any AP series sum of series is =

Sn =n [a+l]/2 Where n= number of terms

a =first term and .. l= last term

Sum of odd = 101 (1+201)/2= 101×101 =10201

----> So your Answer is 10,201

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