Math, asked by Anonymous, 4 months ago

Find the sums

a) 51+52+53+............+80

b) 53+54+55+............+82

c) 102+104+106+...........+160​

Answers

Answered by Anonymous
40

Question A

  • 51 + 52 + 53 + ........ + 80

Answer

a = 51 = first term

d = 1 = common difference

an = 80

n = number of terms

___________________________

Finding ( n )

an = a + ( n - 1 ) × d

80 = 51 + ( n - 1 ) × 1

80 = 51 + n - 1

80 - 51+1 = n

30 = n

Now .( sn ) sum of numbers.

sn = n/2 ( a + an )

sn = 30/2 ( 51 + 80 )

sn = 15 × 131 = 1965

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Question. B

53+ 54 + 55 + ........ + 82

Answer

a = 53 = first term

d = 1 = common difference

an = 82

n = number of terms

___________________________

Finding ( n )

an = a + ( n - 1 ) × d

82 = 53 + ( n - 1 ) × 1

82 = 53 + n - 1

82 - 53 +1 = n

30 = n

Now( sn ) sum of numbers.

sn = n/2 ( a + an )

sn = 30/2 ( 53 + 82 )

sn = 15 × 135 = 2025

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Question C

102+104+106+...........+160

Answer.

a = 102 = first term

d = 2 = common difference

an = 160

n = number of terms

___________________________

Finding ( n )

an = a + ( n - 1 ) × d

160 = 102 + ( n - 1 ) × 2

160 = 102 + 2n - 2

160 - 102 + 2 = n

60 = n

Now( sn ) sum of number

sn = n/2 ( a + an )

sn = 60/2 ( 102+ 160 )

sn = 30 × 262 = 7860.

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( A )sum of number is --- 1965

( B )sum of number is --- 2025

( C )sum of number is ---- 7860

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