Find the sums given below: 34 plus 32 plus 30 plus....plus 10
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Find the sums given below (i) 7 + 101/2 + 14 + … ... 10 Here, a = 34 d =32 – 34 = –2 Also, last term = = 84 So, we use the formula S = /2 ...
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As it is a decreasing A.P. ,
a=34. d= -2. and l=10
Now to find the no. of terms,
l=a+(n-1)d
10=34+(n-1)(-2)
-24=(n-1)(-2)
12=n-1
n=13
As the last term is given ,
sum= n*(a+l)/2
=13*(34+10)/2
=13*44/2
=13*22
= 286
I hope it helps.
a=34. d= -2. and l=10
Now to find the no. of terms,
l=a+(n-1)d
10=34+(n-1)(-2)
-24=(n-1)(-2)
12=n-1
n=13
As the last term is given ,
sum= n*(a+l)/2
=13*(34+10)/2
=13*44/2
=13*22
= 286
I hope it helps.
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