Math, asked by nagarajagali5, 10 months ago

Find the sums given below:
7+10 1/2+14+.... +84​

Answers

Answered by Cynefin
94

✯Answer✯

Given:

  • 7+ 10 1/2+ 14...84

To find:

  • Sum of all terms of AP.

✯Concept to know✯

Before solving, we must analyze that what type of series or progression is this, so that we can easily find out the sum of all trms using formulas.

Here,

 \large{\mapsto{\sf{1st \: term(a1)= 7}}} \\   \\  \large{\mapsto{\sf{2nd \: term(a2) = 10 \frac{1}{2} }}} \\  \\ \large{\sf{\mapsto{3rd \: term = 14}}} \\  \\   \large{\sf{\implies{a2 - a1 = 10  \frac{1}{2}  - 7 = 3  \frac{1}{2} }}}  \\  \\  \large{ \sf{ \implies{a3 - a2 = 14 - 10 \frac{1}{2}  = 3 \frac{1}{2} }}} \\  \\  \large{ \sf{ \red{ \star{ \: \: a2 - a1 = a3 - a2 = 3  \frac{1}{2} }}}}

❋Hence, it is an Arithmetic progression, as the consecutive terms have common difference.

General formula for AP,

 \large{ \boxed</strong><strong>{</strong><strong>\</strong><strong>purple</strong><strong>{an = a + (n - 1)d}</strong><strong>}</strong><strong>}

Note:

Symbols have their usual meanings

By using this formula,

 \large{ \mapsto{ \sf{84 = 7 + (n - 1)3 \frac{1}{2} }}} \\  \\  \large{ \mapsto{ \sf{84 = 7 + (n - 1) \frac{7}{2} }}} \\  \\  \large{ \mapsto{ \sf{77 =  \frac{7}{2} (n - 1)}}} \\  \\  \large{ \sf{ \mapsto{ \cancel{77} \:  \: 11 \times  \frac{2}{ \cancel{7}}  = n - 1}}} \\  \\  \large{ \sf{ \mapsto{ \boxed{n = 23}}}}

Sum of n terms of an AP

 \large{ \sf{ \boxed</strong><strong>{</strong><strong>\</strong><strong>purple</strong><strong>{Sn =  \frac{n}{2}  \:  \{ \: 2a + (n - 1)d  \: \} }</strong><strong>}</strong><strong>}}

Note:

Symbols have their usual meaning.

By using the formula,

 \large{ \sf{ \mapsto{S23 =  \frac{23}{2}  \{2 \times 7 + (23 - 1)3  \frac{1}{2} \} }}} \\  \\  \large{ \sf{ \mapsto{S23 =  \frac{23}{2}  \{ \: 14 +11\:  \cancel{ 22} \times  \frac{7}{ \cancel{2}} \} }}} \\  \\  \large{ \sf{ \mapsto{S23 =  \frac{23}{2}  \{14 + 77}}} \} \\  \\  \large{ \sf{ \mapsto{S23 =  \frac{2093}{2} }}} \\  \\  \large{ \sf{ \mapsto{ \boxed{ \green{S23 = 1046.5}}}}}

✯So final answer✯

 \large{ \boxed{ \bf{Sum \: of \: all \: terms = 1046.5}}}

Answered by bathamabhay307
11

hope it may help you this answer is divided into 4 parts second answer is divided into two parts hope you understand which is the first part of second answer and second part of and also have a nice day please mark my answer as a bridge list and rate also ️

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