Question

Find the sums of all natural numbers between 300 and 600which are divisible by 7​

Answer 1

Answer:

Step-by-step explanation:

a=301=t1

tn =595

d=7

tn =301+(n-1)7

(595-301)/7=n-1

294/7=n-1

n-1=42

n=43

Sn =n/2(t1 +tn)

=43/2(301+595)

=43/2*896

43*448

=19264

Answer 2

Answer:

19,264

Step-by-step explanation:

301=7×43+0

600=7×85+5

85- 42=43 terms

; the series is...... in arithmetic progression

series

301,308............. 595

sn=n/2(a+l)

;43/2(301+595)

;43/2(896)

;43(448)

;19,264