Find the sun of all 3 digit nos. which leaves the same remainder 2 when
divided by 5
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8
Answer :
Sum of all three digit numbers which leaves remainder 2 when divided by 5 is 98910
Explanation :
Given that :
Three digit numbers which leave the remainder 2 when divided by 5 are 102, 107, 112,117......, 997.
102, 107, 112,......, 997 is an A.P
To Find :
Find the sum of all 3 digit nums.
Solution :
As given that So,
In this A.P
=> (First term) a = 102
=> (Common difference) d = 5
=> (last term ) I = 997.
Now,
Sum of all 3 digit numbers which leaves remainder 2 when divided by 5 :
Sum of all three digit numbers which leaves remainder 2
When divided by 5 is 98910 :
∴ Sum of all three digit numbers which leaves remainder 2 when divided by 5 is 98910
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