Question

find the sun of remainders when x^3-3x^2+4x-4 is divided by (x-1) and (x+2)
i"ll mark brainlist​

Answer 1

Answer:

-34

Step-by-step explanation:

Let us find the zero of (x - 1).

x - 1 = 0

x = 1

Remainder when p(x) is divided by x - 1 = p(1)

Now, let us find the zero of (x + 2).

x + 2 = 0

x = -2

Remainder when p(x) is divided by x + 2 = p(-2)

So, the sum of remainders =

p(1) + p(-2)

= (1^3 - 3×1^2 + 4×1 - 4) + [(-2)^3 - 3×(-2)^2 + 4×-2 - 4]

= (1 - 3 + 4 - 4) + [-8 - 12 - 8 - 4]

= -2 + (-32)

= -2 - 32

= -34