find the Supplementary angle whose one angle is twice the other
Answers
Answered by
2
let the one angle be 'x'
other angle = twice of x = 2x
sum of supplementary angles = 180°
x + 2x = 180°
3x = 180°
x = 60°
Answer: required angle = 60°
other angle = twice of x = 2x
sum of supplementary angles = 180°
x + 2x = 180°
3x = 180°
x = 60°
Answer: required angle = 60°
Answered by
0
Let the first angle be "x"
Another angle be "2x"
x+2x=180
3x=180
x=180/3
x=60.
2x=60×2
120
Another angle be "2x"
x+2x=180
3x=180
x=180/3
x=60.
2x=60×2
120
Similar questions