Question

Find the supplementary angles in which one angle is 40° more than the other angle

Answer 1

Answer:

Supplementary Angle= 180 deg

so let the 1st no be x and another no be x+40

so

$x + x + 40 = 180 \\ 2x = 180 - 40 \\ 2x = 140 \\ x = \frac{140}{2} \\ x = 70$

So first angle is 70 degrees

and second angle is 70+40=110 degrees

Answer 2

Answer:

70° and 110°

Step-by-step explanation:

let one angle be x.

the other angle is 40 more than the first

other angle = x + 40

since the angles are supplementary their sum will be equal to 180°

x + x + 40 = 180

2x + 40 = 180

2x = 140

x = 70

thus we got the value of one angle that is 70°

other angle is 40 more so 70 + 40 that is equal to 110°

hence the angles are

70° and 110°